????LOGARITHMS FOR MILITARY COMPETITIONS -(ESA, EEAR, EAM AND ESPCEX)

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Praticando Matemática com Maicon Meneguci

Published on Streamed live on Mar 20, 2020
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Hello student!! Do you want to pass the military exams? In this class I will teach you some military exam questions so you can ace the military exams. ???? GET THE BEST MATHEMATICS COURSE FOR MILITARY EXAMS: https://praticandomatematica.com/ ???? BEST PLAYLIST FOR MILITARY EXAMS: https://bit.ly/3bNf0LK LOGARITHMS: https://bit.ly/3a0SnlD ???? ESA: https://bit.ly/36iVaFC ???? EEAR: https://bit.ly/2HCCRQw ???? ESPCEX: https://bit.ly/34j1CL0 ✅ TELEGRAM GROUPS FOR YOU TO DOWNLOAD MATERIALS!! ESA/EEAR/ESPCEX: https://t.me/pratmatesa ???? FOLLOW ON INSTAGRAM : https://www.instagram.com/praticandom... 1-Let a, b, and c be positive real numbers, with b ≠ 1. If logb a = 1.42 and log b c = -0.16, then the value of log b a2b/c is a) 3 b) 4 c) 5 d) 6 2-The value of a) 3/4 b) 9/4 c) 0 d) -3 The value of the expression log2(1/2) + log8(32) is: a) 1 b) 5/3 c) 2/3 d) - 1 e) 0 If log23 = a and log25 = b, then the value of log0.575 is a) + b b) − a + 2b c) a − b d) a − 2b e) − a − 2b Adopting log2=x and log3=y, the value of log5 120 will be given by: a)2x+y/ 1-x b)4x+3y/ x+y c) 2x+y+1/ 1-x d) x+2y+1/ 1-y e) x+2y/ 1-y

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