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Hello everyone, welcome to the ZimZim DIY channel. Today I will show you what the results will be if we connect capacitors in parallel and in series. Let's start with parallel connections. Connecting in series I will give 3 examples. Type 1 is parallel connection with the same capacitance and voltage. Suppose you have 5 capacitors with the same value, which is 1,000 uF 25V, connected in parallel. If connected in this way, the capacitance value will be = the sum of the capacitor values. Therefore, the answer will be 5,000 uF and the voltage resistance will be 25V. This method is often used, such as modding a small amp power supply. Type 2 uses C connected in parallel with different capacitance values. If you have capacitors with different values, such as number 1, number 2, number 3 with a capacitance of 1,000 uF 25V and number 4 and number 5 with a capacitance of 2,000 uF 25V, the calculation method will still be the same, which is to add the capacitance values together. Therefore, the answer will be 7,000 uF and the voltage resistance will be 25V. But there will be another case, the third type, which is capacitors with the same charge storage value but different voltage resistance values. That is, if I use the same C value and all C can withstand 25V but there is a C that can withstand 16V, therefore, the voltage value that it can withstand depends on the one with the lowest voltage value. The answer will be equal to 7,000 uF withstands 16V. In summary, the parallel connection of C means that we will connect + collide with + - collide with - in parallel continuously, no matter how many. The capacitance value obtained comes from adding the + values of all C together. It is like we have a new C, which is a larger C. But its total voltage resistance will be calculated from the C with the lowest voltage value, not from the average of all C values. As for connecting C in series, it means connecting plus one collide with minus another, colliding with each other continuously. If you have capacitors with the same value, such as 5 capacitors with a C value of 1,000 uF 25V, connected in series. The capacitance value obtained will be equal to the capacitance value of C divided by the number of C. Therefore, 1000uf divided by 5 equals 200uF. Note that the charge storage will be less, but the voltage that that C can withstand will be the opposite. It will be equal to the total voltage combined, which will be equal to 25V each C x 5 = 125V. It is like we have a large capacitor that can withstand higher voltage. Just the charge storage value, as mentioned, will be less. And for connecting C in series with different capacitance values, it is usually not popular because one C will work harder than the others. Therefore, in this clip, I will not mention it. In conclusion, connecting C in both ways gives completely different results. In any case, friends, try to choose to apply it to suit your work. Thank you to all friends who follow and watch.